Solution: Compute $ \|\mathbf{a} + \mathbf{b} + \mathbf{c}\|^2 = 3 + 2(\mathbf{a} \cdot \mathbf{b} + \mathbf{b} \cdot \mathbf{c} + \mathbf{c} \cdot \mathbf{a}) = 3 + 2\left(\frac{1}{2} + \frac{1}{2} + \frac{1}{2}\right) = 3 + 3 = 6 $. Thus, the norm is $ \sqrt{6} $.

Sun, 03 May 2026 12:08:57 +0000

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