Solution: Set $ \frac{1}{8}D_0 = D_0 \cdot 2^{-t/12} $. Divide both sides by $ D_0 $: $ \frac{1}{8} = 2^{-t/12} $. Note $ \frac{1}{8} = 2^{-3} $, so $ 2^{-3} = 2^{-t/12} $. Equate exponents: $ -3 = -\frac{t}{12} $. Solve for $ t $: $ t = 36 $.

Sun, 03 May 2026 12:08:57 +0000

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