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π° A spacecraft performs a burn to increase its velocity by 350 m/s. If its initial speed was 7,200 m/s, what is its new kinetic energy per kg? Use \( KE = \frac{1}{2} v^2 \).
π° New speed = 7,200 + 350 = 7,550 m/s
π° \( KE = \frac{1}{2} \times (7,550)^2 = \frac{1}{2} \times 57,002,500 = 28,501,250 \, \text{J/kg} \)
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