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Home » \( D^3 \equiv 1 \pmod9 \), and - Parker Core Knowledge

\( D^3 \equiv 1 \pmod9 \), and - Parker Core Knowledge

📅 May 3, 2026 👤 scraface

May 03, 2026

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This is a geometric series: a = 8, r = 1.25, n = 5
Total items = a(r^n - 1)/(r - 1) = 8(1.25^5 - 1)/(0.25)
1.25^2 = 1.5625
1.25^4 = (1.5625)^2 = 2.44140625
1.25^5 = 2.44140625 × 1.25 = 3.0517578125
So, (3.0517578125 - 1) = 2.0517578125
Divide by 0.25: 2.0517578125 / 0.25 = 8.20703125
Multiply by 8: 8 × 8.20703125 = 65.65625
So total ≈ 65.66 items, but since items are whole, and the model allow...
#### 65.65625

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