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discuss briefly a comparison of the two vinegars - Parker Core Knowledge

📅 May 4, 2026 👤 scraface

May 04, 2026

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12a + 3(2 - 3a) = 10 \Rightarrow 12a + 6 - 9a = 10 \Rightarrow 3a = 4...
Then $ b = 2 - 3 \cdot \frac{4}{3} = 2 - 4 = -2 $
From (2): $ \frac{4}{3} - 2 + c = 3 \Rightarrow c = 3 + 2 - \frac{4}{3...
And $ d = 2 $
p(x) = \frac{4}{3}x^3 - 2x^2 + \frac{11}{3}x + 2
Thus, the remainder when $ p(x) $ is divided by $ x^4 - 1 $ is simply...
\boxed{\frac{4}{3}x^3 - 2x^2 + \frac{11}{3}x + 2}
Question: Let $ a $ and $ b $ be complex numbers such that $ a + b = 4...
We know $ a + b = 4 $, and
a^2 + b^2 = (a + b)^2 - 2ab = 16 - 2ab = 10 \Rightarrow 2ab = 6 \Right...

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