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📰 $ t > 4 $, so $ t = 5 $? No: $ t = 4.1 $ is sufficient. But years are discrete? The model is continuous, so the first year when it exceeds is 2005? But 2004 already reaches 3.0. 📰 But $ t = 4.1 $ is in the year 2004 (since $ t = 0 $ is 2000). So the anomaly first exceeds 3.0 during 2004, but the official year is 2004. However, the first full year where its above is 2005? But the model is continuous. Typically, we report when it crosses. 📰 However, at $ t = 4 $, $ T = 3.0 $, so to exceed, $ t > 4 $. The next whole year is 2005, but the model is valid for all $ t $. The smallest year is $ 2000 + 4 = 2004 $, but since its equal at 2004, and increases, the first time it exceeds is in 2004? But exceed means $ > 3.0 $, so $ t > 4 $. Thus, the first full year is not yet 2005? But 2004 is $ t = 4 $. 📰 Bubble Shooter Bubble Shooter Bubble Shooter 4192227 📰 You Wont Believe How Clustertruck Game Online Creates Infinite Funplay Now 9337105 📰 Kim Garfunkel 1844488 📰 Academy Stock 6068793 📰 Ga Lottery Results And Winning Numbers 8080636 📰 Lime Juice You Never Knew You Neededshocking Secrets Make You Drink More 3558274 📰 What Is The Best Tv Streaming Service 7316412 📰 The Express You Never Knew You D Enjoy Heat That Wont Let Go 1744026 📰 Discover The Hidden Truth Behind Icelands Powerful Flag 87937 📰 Ucla Los Angeles Tuition 7892889 📰 This Mysterious Figure Called Maz Kanata Will Shock Youthis Rare Discovery Will Blow Your Mind 4176396 📰 Found A Staggering Used Switch At Half Pricedont Miss It 7190164 📰 Topsters 3 Shocked Everyonediscover The Secret Game Changer Today 1423336 📰 Sands Golf Wisconsin 1607760 📰 Microsoft Device Registration 4353106