We minimize this expression for $ s \in (\sqrt{2}, \sqrt{2}] $, since $ \sin x + \cos x = \sqrt{2} \sin\left(x + \frac{\pi}{4}\right) $, and maximum is $ \sqrt{2} $. Wait — maximum is $ \sqrt{2} $, minimum is 1 (approaching at endpoints), but in the open interval $ (0, \frac{\pi}{2}) $, $ s \in (1, \sqrt{2}) $.

Tue, 05 May 2026 21:35:04 +0000

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