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📰 But $ d(t) = t^3 $ is strictly convex and has no minimum (it decreases on $ (-\infty, 0) $, increases on $ (0, \infty) $), so it does not achieve a minimum. However, the problem states that the **minimum depth is achieved exactly once**, which implies $ d(t) $ has a unique global minimum. But $ t^3 $ has no such minimum. Contradiction? 📰 Wait — unless our initial assumption that $ d(t) = t^3 $ is forced is correct, but it violates the minimum condition. So perhaps $ d(t) $ is not exactly $ t^3 $, but fits it at four points. But a cubic is uniquely determined by four points, so $ d(t) = t^3 $ is the only cubic polynomial satisfying the conditions. 📰 But $ d(t) = t^3 $ has no minimum. Unless minimum depth refers to **local minimum**? But still, $ t^3 $ has no local minimum. 📰 Lookaway App 8661507 📰 180 Euro To Usd 9055691 📰 Whats Inside The Fighting Z The Mind Blowing Moves Everyones Raving About 9518370 📰 Mozilla Firefox For Mac Download 5874171 📰 Hmartist Wow Usdiscover The Masterpiece Behind Every Single Piece 1598472 📰 You Wont Believe What Just Happened A Beloved Series Canceled Overnight 5576492 📰 Bank Of America Online Banking Customer Service Phone Number 8175956 📰 Frylands Forest Fc Players 1658746 📰 Swords And Sandals 2 Cheats 3587738 📰 Hamburger Button 2851703 📰 Baton Rouge Obits 4770314 📰 Rojadirecta Why This Trend Is Going Viral Faster Than You Think 4560244 📰 You Wont Believe Who Played The Lead In The Bee Movie 6504595 📰 Orilley 5070158 📰 Arbitrage 2012 4117855