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where to watch the buccaneers - Parker Core Knowledge

📅 May 2, 2026 👤 scraface

May 02, 2026

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📌 Thus, the remainder is $ \boxed{2} $.Question: What is the smallest four-digit number that is divisible by the least common multiple of 12 and 18, and also leaves a remainder of 3 when divided by 7?

📌 To find the smallest four-digit number satisfying the given conditions, we proceed in steps.

📌 \text{lcm}(12, 18) = \frac{12 \cdot 18}{\gcd(12, 18)} = \frac{216}{6} = 36

📌 So, the number must be divisible by 36 and leave a remainder of 3 when divided by 7. That is:

📌 n \equiv 0 \pmod{36}, \quad n \equiv 3 \pmod{7}

📌 We solve this system using the Chinese Remainder Theorem. Since 36 and 7 are coprime, there is a unique solution modulo $36 \cdot 7 = 252$.

📌 Let’s find $n$ such that:

📌 Let $n = 36k$. Then:

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