y^2 - 4y = (y - 2)^2 - 4 - Parker Core Knowledge
Understanding the Equation: y² - 4y = (y - 2)² - 4
A Step-by-Step Algebraic Breakdown and Simplification
Understanding the Equation: y² - 4y = (y - 2)² - 4
A Step-by-Step Algebraic Breakdown and Simplification
The equation y² - 4y = (y - 2)² - 4 appears simple at first glance but reveals valuable algebraic structure once analyzed carefully. In this article, we explore the equation from first principles, simplify it step by step, and explain its significance in algebra and functions. Whether you're studying derivatives, vertex form, or solving quadratic equations, understanding this form deepens foundational skills essential for advanced mathematics.
Understanding the Context
What Is the Equation?
We begin with:
y² - 4y = (y - 2)² - 4
On the right-hand side, we see a squared binomial expression — specifically, (y - 2)² — subtracted by 4. This structure hints at a transformation from the standard quadratic form, frequently appearing in calculus (derivative analysis) and graphing.
Step 1: Expand the Right-Hand Side
To simplify, expand (y - 2)² using the binomial square formula:
(a - b)² = a² - 2ab + b²
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So,
(y - 2)² = y² - 4y + 4
Substitute into the original equation:
y² - 4y = (y² - 4y + 4) - 4
Step 2: Simplify the Right-Hand Side
Simplify the right-hand expression:
(y² - 4y + 4) - 4 = y² - 4y + 0 = y² - 4y
Now the equation becomes:
y² - 4y = y² - 4y
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Step 3: Analyze the Simplified Form
We now have:
y² - 4y = y² - 4y
This is an identity — both sides are exactly equal for all real values of y. This means the equation holds true regardless of the value of y, reflecting that both expressions represent the same quadratic function.
Why This Equation Matters
1. Function Equivalence
Both sides describe the same parabola:
f(y) = y² - 4y
The right-hand side, expanded, reveals the standard form:
y² - 4y + 0, which directly leads to the vertex form via completing the square.
2. Vertex Form Connection
Start from the expanded right-hand side:
(y - 2)² - 4 is already in vertex form: f(y) = a(y - h)² + k
Here, a = 1, h = 2, k = -4 — indicating the vertex at (2, -4), the minimum point of the parabola.
This connects algebraic manipulation to geometric interpretation.
3. Use in Calculus – Finding the Derivative
The form (y - 2)² - 4 is a shifted parabola and is instrumental in computing derivatives. For instance, the derivative f’(y) = 2(y - 2), showing the slope at any point.
